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6b^2-7b=24
We move all terms to the left:
6b^2-7b-(24)=0
a = 6; b = -7; c = -24;
Δ = b2-4ac
Δ = -72-4·6·(-24)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-25}{2*6}=\frac{-18}{12} =-1+1/2 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+25}{2*6}=\frac{32}{12} =2+2/3 $
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